-2x^2+30X=3

Solution for -2x^2+30X=3 equation:

-2x^2+30x=3

We move all terms to the left:

-2x^2+30x-(3)=0

a = -2; b = 30; c = -3;
Δ = b2-4ac
Δ = 302-4·(-2)·(-3)
Δ = 876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{876}=\sqrt{4*219}=\sqrt{4}*\sqrt{219}=2\sqrt{219}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{219}}{2*-2}=\frac{-30-2\sqrt{219}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{219}}{2*-2}=\frac{-30+2\sqrt{219}}{-4}
$